Thanks John and Dan,
> info.eznote.{p1}=[(source {p}:p{ {p0}-1 })]
This doesn't work. :(
Cheers,
linly
On 2月9日, 上午4時37分, The Editor <[email protected]> wrote:
> On Sun, Feb 8, 2009 at 11:58 AM, jacmgr <[email protected]> wrote:
>
> > I have 2 ideas
>
> > [if more {p0} 1]
> > [if* more {p0} '4']info.eznote.{p1}{p4}[if*]
> > [if* equal {p0} '4']info.eznote.{p1}{p3}[if*]
> > [if* equal {p0} '3']info.eznote.{p1}{p2}[if*]
> > [if* equal {p0} '2']info.eznote.{p1}{p1}[if*]
> > [else]
> > info.eznote.{p1}{p1}
> > [if]
>
> Johns code looks more like what you are trying to do... Though we may
> not be discerning exactly what you want. It seems easier to me to read
> it this way though:
>
> [if more {p0} 4]info.eznote.{p1}{p4}[if]
> [if equal {p0} 4]info.eznote.{p1}{p3}[if]
> [if equal {p0} 3]info.eznote.{p1}{p2}[if]
> [if less {p0} 3]info.eznote.{p1}{p1}[if]
>
> > The idea below doesn't work, but maybe someone else has clue. Anyway
> > the below is just future ideas.
> > Instead of all ifs, maybe one statement like:
> > info.eznote.{p1}{p{p0}} //this should work but doesn't???
>
> This doesn't write, but as my other post suggests you can do
> info.eznote.{p1}{{p}:{p0}}
>
> I'll likely change the markup rules to allow your simpler example
> however. It just loosens things up.
>
> Of course, this doesn't match the criteria above as it should be p(p0
> - 1), not p(p0).
>
> > or
> > info.eznote.{p1}{p[(math {p0} - 1)]} //just future idea
>
> This one won't work because variables are processed before functions,
> so you'll end up with
>
> info.eznote.p1{p3} (ie the 3 is inserted to late for the variables
> markup to catch the {p3}.
>
> But after a bit of testing, I think you could probably do this:
>
> info.eznote.{p1}=[(source {p}:p{ {p0}-1 })]
>
> Funny how some things can be a bit tricky sometimes... Love a good puzzle
>
> Cheers,
> Dan
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