On 4 Jul 2003, Gabriel Dos Reis wrote:
> "Toon Knapen" <[EMAIL PROTECTED]> writes:
>
> | > seems like this code
> | >
> | > template< typename T >
> | > bool is_nan( const T& v )
> | > {
> | > return std::numeric_limits<T>::has_quiet_NaN && (v != v);
> | > }
> | >
> | > does not work correctly on some machines.
> |
> | Could you be more specific. On which machines for instance ?
>
> If v is a signalling NaN, and you're for example using the SPARC
> architecture for example, you might get a trap.
>
> -- Gaby
Just to avoid any kind of misunderstanding, the interval library don't use
signaling NaN.
Regards,
Guillaume
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