Larry Evans wrote:
I've got a general template class:
template<typename X, typename Y>class A{...};
and a specialization of that class:
template<typename X>class A<X,SpecificY>{...};
and I want to have a "see also" in the doc for the general template.
The <classname>A</class> provides a link to the general template,
but how do I provide the link to the specialization. I've tried,
in A.specialization.xml to put:
<class-specialization
name="A"
id="A.specialization"
>
<template>
<template-type-parameter name="X"/>
</template>
<specialization>
<template-arg>X</template-arg>
<template-arg>SpecificY</template-arg>
</specialization>
and then use <link linkend="A.specialization">A</link>
in A.xml; however, I get the error:
Error: no ID for constraint linkend: A.specialization.
What should I do?
Hi Larry!
I took a quick peek at your problem (BoostBook stylesheets and doxygen
docs are not exactly my specialty...). It looks like supplying an ID in
<class-specialization> is not enough. I think you'll need to hack the
stylesheet (somewhere in type.xsl, though I haven't zeroed in on the
exact location yet) to make it emit an <anchor> or something like that
(no DocBook expert either), containing the ID you wish to reference.
After that you should have no problem with your <link>.
I hope that will help you for now... I'll take a deeper look at it later.
Regards,
João
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