"David Abrahams" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > You can get an idea of the intended semantics of this dance by looking > at libs/python/test/member_function_cast.cpp. The idea is that if f > is a member function, and its class is a base class of Target, it > will be implicitly converted to a pointer-to-member of Target. > Otherwise it will be left alone. > > We are going to drop support for CodeWarrior 7 in the next version of > Boost.Python anyway, so you could reimplement those semantics with a > much more straightforward interface that works with BCC. I think you > should be able to make > > member_function_cast<Target>(f) > > work
Thanks. It certainly helps to have a clearer understanding of what is going on here. I'll see if I can come up with a "simpler" BCC-specific approach. Chris _______________________________________________ Unsubscribe & other changes: http://lists.boost.org/mailman/listinfo.cgi/boost
