Gabriel Dos Reis <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > "jvd" <[EMAIL PROTECTED]> writes: > > | Dear boosters, > | > | seems like this code > | > | template< typename T > > | bool is_nan( const T& v ) > | { > | return std::numeric_limits<T>::has_quiet_NaN && (v != v); > | } > | > | does not work correctly on some machines. > > Yes. It is an incorrect (unfortunately popular) implementation. > Right. We should say that more often. It is incorrect however popular.
Most compilers provide a non standard extension for this purpose. For instance, Borland uses _isnan. In general, these extensions are found on <float>. The best approach, IMO, is to have a boost::is_nan() with compiler specific implementations. Fernando Cacciola _______________________________________________ Unsubscribe & other changes: http://lists.boost.org/mailman/listinfo.cgi/boost
