> | > Do I understand correctly that
> | >
> | > BOOST_CHECK_CLOSE(v1, v2, 2. * std::numeric_limits::epsilon() );
> | >
> | > would check that the absolute difference between v1 and v2 is not
> | > more than two eps?
> | >
> | > Paul
> |
> | No. BOOST_CHECK_CLOSE performs relative errors comparison. See
> | http://www.boost.org/libs/test/doc/floating_point_comparison.htm
> |
> | (Ignore part that tries to calculate the tolerance based on
> number of
> | rounding errors)
> |
> | Gennadiy.
>
> Yes of course - sorry. So how would I achieve the above test?
Something about these lines:
bool
struct my_fpt_compare
{
explicit my_fpt_compare( float t ) : m_tolerance( t ) {}
bool operator( float a, float b )
{
return std::fabs( a - b ) < m_tolerance;
}
float m_tolerance;
}
// Instead you could write free function and use boost::bind to bind the
tolerance
...
BOOST_CHECK_PREDICATE( my_fpt_compare( 2. * std::numeric_limits::epsilon()
), 2, ( v1, v2 ) );
Gennadiy.
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