On Wed, 18 Jul 2001, Dan Sugalski wrote:
> It also means that perl may be able to do:
>
> (@foo, @bar) = baz();
>
> and really have data go into both @foo and @bar--since we don't flatten, it
> means array and hash elements don't lose their grouping on assignment or
> subroutine returns, so we can figure out how to do this right. (Whether we
> *will* or not is a separate issue, and that's Larry's problem. I'm just
> going to make sure the mechanism is there if he chooses to expose it)
Very interesting. So, if the mechanism is going to be there anyway, will
there be a way to poke at it if Larry decides not to expose it?
It's tantalizing to know what interesting things will be going on under
the hood, and yet we might not be able to work with some of them...
--
Chris Devers [EMAIL PROTECTED]
