Sorry.. rereading this tells me my answers may not have overly helped... are you just trying to verify input, or actually parse it and store it somehow?
On Fri, Oct 11, 2002 at 02:20:13PM -0400, Ranga Nathan wrote: > Thanks guys that was quick response; > In the context of Any2XML, which forces me to use a regex for top-down > parsing, I need to use regex. Even if the regex is slow, that is fine. > If it is impossible to do this in regex, of course, I would resort to > split(). > > Can this be done using regex? Why does \1 not work? These are my > questions. > > Thanks again... > > ---Closing information gaps----- > Ranga Nathan, Reliance Technology > >>SEVIS solution now! http://goreliance.com > >>Live demo at http://any2xml.com/docs/timesheet_demo.shtml<< > >>Get free COBOLExplorer at http://goreliance.com/download-products << > > > -----Original Message----- > > From: [EMAIL PROTECTED] > > [mailto:[EMAIL PROTECTED]] On Behalf Of Mark Aisenberg > > Sent: Friday, October 11, 2002 2:15 PM > > To: [EMAIL PROTECTED] > > Subject: RE: [Boston.pm] Calling regex gurus ..A regex question.. > > > > > > Your '\1' question aside: > > Your solution requires you to know the number of patterns in > > the string. For long strings, a regex could be slow. Why not > > just 'split' on whitespace into an array and then use array > > indices to easily extract the items you want? > > > > > > > > > > -----Original Message----- > > From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] > > On Behalf Of Ranga Nathan > > Sent: Friday, October 11, 2002 1:42 PM > > To: [EMAIL PROTECTED] > > Subject: [Boston.pm] Calling regex gurus ..A regex question.. > > > > > > I need to parse a string that has multiple occurrences of a > > pattern that is determined by an embeded count. For example: > > > > 02 s1n1 s1n2 3 s2n1 s2n2 s2n3 1 s3n1 4 s4n1 s4n2 s4n3 s4n4 > > > > 02 is the count and I need to extract s1n1 and s2n2 > > > > 3 is the count and I need to extract s2n1, s2n2 and s2n3 > > > > And so on. > > > > So I tried to do: > > $var = > > /(.*?)\s+((?:.*?\s+){\1})(.*?)\s+((?:.*?\s+){\3})(.*?)\s+((?:. > > *?\s+){\5} > > )/; > > > > And was expecting "02" "s1n1 s1n2 " "3" "s2n1 s2n2 s2n3 " "1" > > "s3n1 " "4" "s4n1 s4n2 s4n3 s4n4 " as matches. > > > > This does not work. > > The \1, \2 etc are not evaluated as 'iterators'. I tried the > > experimental ?{} too. > > > > > > > > ---Closing information gaps----- > > Ranga Nathan, Reliance Technology > > >>SEVIS solution now! http://goreliance.com > > >>Live demo at http://any2xml.com/docs/timesheet_demo.shtml<< > > >>Get free COBOLExplorer at http://goreliance.com/download-products << > > > > _______________________________________________ > > Boston-pm mailing list > > [EMAIL PROTECTED] http://mail.pm.org/mailman/listinfo/boston-pm > > > > > > > > _______________________________________________ > > Boston-pm mailing list > > [EMAIL PROTECTED] http://mail.pm.org/mailman/listinfo/boston-pm > > > > _______________________________________________ > Boston-pm mailing list > [EMAIL PROTECTED] > http://mail.pm.org/mailman/listinfo/boston-pm -- ___ __ __ __ _ _ ____ _ _ ____ ____ / __)( )( ) /__\( \/ )( ___) ( \( )( ___)(_ _) \__ \ )(__)( /(__)\\ / )__) ) ( )__) )( (___/(______)(__)(__)\/ (____)()(_)\_)(____) (__) You must know your limits to break through them. _______________________________________________ Boston-pm mailing list [EMAIL PROTECTED] http://mail.pm.org/mailman/listinfo/boston-pm
