* Greg London <email at greglondon.com> [2005/03/07 10:43]: > > Palit, Nilanjan said: > > $> perl -e '$x=1; $y=$x+++1; print "x=$x, y=$y\n"' > > Bummer. I just got a ding on your interview. > How do you parse $x+++1 ?
$ perl -MO=Deparse,p -e '$x=1; $y=$x+++1; print "x=$x, y=$y\n"' $x = 1; $y = $x++ + 1; print "x=$x, y=$y\n"; -e syntax OK :) (darren) -- 1. Everything depends. 2. Nothing is always. 3. Everything is sometimes.
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