On Thu, Sep 21, 2006 at 11:30:08AM -0400, Alex Brelsfoard wrote:
> I know I've done this before, but I'm having a hard time finding my
> old code, and am not using the right search terms on google... All I
> am looking for is the quickest method to find the user who is calling
> this script.
> This is a script that will only ever be run by shell command on a
> Linux system.
Well, perlvar points out $< and $>:
$REAL_USER_ID
$UID
$< The real uid of this process. (Mnemonic: it’s the uid you came
from, if you’re running setuid.) You can change both the real
uid and the effective uid at the same time by using
POSIX::setuid(). Since changes to $< require a system call,
check $! after a change attempt to detect any possible errors.
$EFFECTIVE_USER_ID
$EUID
$> The effective uid of this process. Example:
$< = $>; # set real to effective uid
($<,$>) = ($>,$<); # swap real and effective uid
You can change both the effective uid and the real uid at the
same time by using POSIX::setuid(). Changes to $> require a
check to $! to detect any possible errors after an attempted
change.
(Mnemonic: it’s the uid you went to, if you’re running setuid.)
$< and $> can be swapped only on machines supporting
setreuid().
Once you have the UID, you can use the getpwuid to get the username or
the whole passwd entry.
--
Dan Boger
[EMAIL PROTECTED]
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