Alex and Joseph, I think you left a little piece but an important one out of your formula examples. Because of order of precedents rules, you need to place the number after the caret in parenthesis if using a fractional value. This forces the division inside the parenthesis to be done first. Otherwise, you end up with a wrong answer. For example: cube root of 125 would be solved by either of the following methods:
125^(1/3)= 125^.333333333= Note that in the second example with the decimal value, while parenthesis were not needed because there was no need to resolve a forced precedents to do the division there first, it took multiple threes after the decimal point to avoid rounding errors. Try the same line but only using a .3 after the caret and see what you get. 125^.3= This example will give you a wrong answer due to rounding errors. If the number divides out without endless carries into infinity, you don't need to use multiple digits after the decimal point. For example, another way to get a square root could use either of the following formulas: 64^(1/2)= 64^.5= Using this caret method you are effectively raising a number to a power but because the power you are raising it to is less than one, you end up with square, cube, etc. roots. Simply use the value after the slash to find that root value; (1/4) for forth root etc. Hope this helps. Richard Ehrler On Tue, 11 Jan 2011 09:41:24 -0500, Alex Hall wrote: >I believe you just raise it to 1 over the root. Examples: >sqrt(4) = 4^1/2 >cbrt(27) = 27^1/3 >and so on. Remember that the fraction bar is backspace-3-4, and the >slashes above are meant to be that, not the regular division slash. > >On 1/11/11, Joshua Klander <[email protected]> wrote: >>Hi list. Is there any way to find the root of a number in the >>scientific calculator? I know that you can find the square root, >>but can you find the cube root, fourth root, etc? I have not seen >>this feature in the calculator, but I figured I would ask anyway. >>I am working with finding roots of real numbers in my Algebra >>class, so I'm hoping there is a way to do this.
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