The Fool wrote:
>
>> Consider three nodes, A,B,C.
>
> we have 3 starting nodes
> we have 2 second nodes
> we have 1 third node
>
> 3 * 2 * 1 = 6 = 3!
>
Why should the brain use _all_ the nodes?
You might use nodes A,C.
So, it's 2^n and not n!
Wait!!! Maybe - in a four-node brain [a blonde
women pregnant with three blonde girl babies] -
you could use A-B and C-D. So, the number is
bigger than 2^n.
Alberto Monteiro
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