On Jul 7, 2012, at 2:43 PM, Christopher Sean Morrison wrote:

> On Jul 7, 2012, at 1:59 PM, phoenix wrote:
> 
>>> Yeah, bad example.  Thanks for the correction -- I was off on my exterior 
>>> case but going for the case you described (r1=50; r2=25; |H|=25).  However, 
>>> you say that the ray-tracing result is a sphere, but also a "smoothened" 
>>> one?  What does that mean?  Screenshot?
>> 
>> This case is not quite obvious for "smoothened". But you can still find that 
>> their size is the same, and the sphere (the second image) can be considered 
>> as what we get if we "smoothened" the solid in the first image.
>> <29FFF409@C034847E.EE78F84F>  <2A02FE05@C034847E.EE78F84F>
> 
> Ah, I see what you mean -- not the word I'd use (maybe "un-dent"), but I get 
> it now. ;)
> 
> For that instance, it looks like the wireframe algorithm is just sucky.  
> Probably trivial fix for the fully-enclosed case.

As I went to write a note that the wireframe was wrong, I found myself in 
disagreement (with myself).  I think the wireframe is right and the 
rendering/sphere is wrong.  If r1=50; r2=25; and |H|=1; I'd expect two fused 
half-spheres of radius 50 and 25 with a 1 unit "steep" transition where they 
fuse.

Cheers!
Sean


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