The following gives a syntax error:
*((1 1) (1 0))/¨'ab' 'cd'*
SYNTAX ERROR
(1 1) (1 0)/¨'ab' 'cd'
^ ^
But, assuming the following function:
∇Z←X sel Y
Z←X/Y
∇
This works:
*((1 1) (1 0))sel¨'ab' 'cd'*
ab c
Regards,
Elias
