The following gives a syntax error:

      *((1 1) (1 0))/¨'ab' 'cd'*
SYNTAX ERROR
      (1 1) (1 0)/¨'ab' 'cd'
      ^           ^


But, assuming the following function:

∇Z←X sel Y
Z←X/Y
∇


This works:

      *((1 1) (1 0))sel¨'ab' 'cd'*
 ab c


Regards,
Elias

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