The only way to make it more consistent is to make behaviours that today are allowed into an error.
What would you expect ⊃'333' '55555' to do? Regards, Elias On 12 May 2014 22:43, Blake McBride <blake1...@gmail.com> wrote: > Thanks. I have to say, with no reflection on present company, I am about > as frustrated and disgusted with nested arrays, as defined by IBM, as I > could be. Having enclose do one thing for all arrays and another for > scalars has caused me endless hours of frustration. (Isn't a scalar just a > zero dimension array?) How much time has one to spend making enclose do > what comes naturally to ones mind? Now I find that disclose actually > modifies data beyond the ability to reconstruct it. In your example, if > one string were a different length than the other, APL will lengthen it to > match the longest upon disclose. The original length of each string is > lost forever. Why stop there? Why not change a 4 to a 7? > > Having enclose and disclose uniformly add and remove layers of boxing only > is simple, consistent, predictable, useful, and easy to understand. If I > add 3 and then subtract 3 I end up with the same number. But if I enclose > and then disclose, I end up with something different - sometimes. Imagine > that! > > '333' '55555' > ┌→────────────┐ > │┌→──┐ ┌→────┐│ > ││333│ │55555││ > │└───┘ └─────┘│ > └∊────────────┘ > ⊃'333' '55555' > ┌→────┐ > ↓333 │ > │55555│ > └─────┘ > (⊃'333' '55555')[1;] > ┌→────┐ > │333 │ > └─────┘ > ⍴(⊃'333' '55555')[1;] > ┌→┐ > │5│ > └─┘ > > > There are ways to rationalize almost anything. IMO, the IBM nested array > approach is confusing, unpredictable, and renders it a tool of very careful > last resort. > > I know there has been debate about this in the past, and I am not looking > to resurrect it. It is a real shame IBM chose the path it chose. > > Blake > > > > On Mon, May 12, 2014 at 5:08 AM, Jay Foad <jay.f...@gmail.com> wrote: > >> APL2's Disclose (Dyalog calls it Mix) will convert a vector of vectors >> into a matrix: >> >> ⊃'timor' 'mortis' >> ┌→─────┐ >> ↓timor │ >> │mortis│ >> └──────┘ >> >> Your second application of Disclose is applied to a 1-vector of >> 1-vectors (,⊂,7), so it returns a 1x1 matrix. >> >> Jay. >> >> On 12 May 2014 06:03, Blake McBride <blake1...@gmail.com> wrote: >> > ⊃⊃⊂,⊂,7 >> > ┌→┐ >> > ↓7│ >> > └─┘ >> > ⍴⊃⊃⊂,⊂,7 >> > ┌→──┐ >> > │1 1│ >> > └───┘ >> > >> > >
