The issue here seems to be that since test is a nihilic function returning
0, the following call:
test/0
Is equivalent to the following:
{0⊣⍵}/0
which returns a single 0, since the /-reduction on a scalar is the value
itself.
However, the following:
(test)/0
is equivalent to:
0/0
because (test) evaluates before /, resulting in ⍬.
Regards,
Elias
On 5 August 2014 15:39, David B. Lamkins <[email protected]> wrote:
> Maybe I've misunderstood some APL2 corner case, but the behavior of the
> attached program seems wrong.
>
>
