I rather like your second solution. It's faster than mine, and sorts the items
for free too!
Well done!
Louis
> On 6 Jul 2017, at 23:54, Ala'a Mohammad <amal...@gmail.com> wrote:
>
> Oops, the second solution should be
>
> (1+c[x]) ⊂ s[x←⍋c]
>
> Ala'a
>
>> On Fri, Jul 7, 2017 at 1:38 AM, Ala'a Mohammad <amal...@gmail.com> wrote:
>> Hi,
>> Another two ways, Not as compact or optimized, but generate the same output
>> 1)
>> G groups, C categories, and S strings
>>
>> G←(⍴∪C)⍴⊂⍬ ◊ C {G[⍺]←⊂(⊃G[⍺]),⊂⍵}¨S ◊ G
>>
>> I forgot how to suppress the middle output
>> or in a function
>>
>> ∇ groups ← categories group items
>> groups ← (⍴∪categories)⍴⊂⍬
>> categories {groups[⍺]←⊂(⊃groups[⍺]),⊂⍵}¨ items
>>
>> 2)
>> (1+C[x]) ⊂ S[(⍳⍴C)[x←⍋C]]
>>
>> Best wishes,
>>
>> Ala'a
>>
>>> On Wed, Jul 5, 2017 at 2:48 PM, Louis de Forcrand <ol...@bluewin.ch> wrote:
>>> Is it important that they be grouped in the order specified by the key?
>>> If not, this should do (with C the categories and S the strings):
>>>
>>> (⊂[1]C∘.=∪C)/¨⊂S
>>>
>>> If they must be ordered, then this can do it:
>>>
>>> (⊂[1]C∘.=U[⍋U←∪C])/¨⊂S
>>>
>>> In addition, the categories don’t have to be numbers.
>>>
>>> Note that Dyalog’s (dyadic) key function is equivalent to this, with L being
>>> the operator’s left operand:
>>>
>>> L¨(⊂[1]C∘.=∪C)/¨⊂S
>>>
>>> Cheers,
>>> Louis
>>>
>>> On 05 Jul 2017, at 11:43, Elias Mårtenson <loke...@gmail.com> wrote:
>>>
>>> I have a list of strings, and a corresponding set of categorisations:
>>>
>>> strings ← 'foo' 'bar' 'abc' 'def' 'ghi' 'jkl'
>>> categories ← 1 1 0 2 1 0
>>>
>>> I now need to group these strings according to category. In other words,
>>> when applying operation X, I need the following output:
>>>
>>> categories X strings
>>> ┏→━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━┓
>>> ┃┏→━━━━━━━━━━┓ ┏→━━━━━━━━━━━━━━━━┓ ┏→━━━━┓┃
>>> ┃┃"abc" "jkl"┃ ┃"foo" "bar" "hgi"┃ ┃"def"┃┃
>>> ┃┗∊━━━━━━━━━━┛ ┗∊━━━━━━━━━━━━━━━━┛ ┗∊━━━━┛┃
>>> ┗∊∊━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━┛
>>>
>>> What is the best way to solve this?
>>>
>>>
