Hi Hans-Peter,
I have added a query syntax to the *)LIBS *command:
* )LIBS 0 ?
library reference 0 stands for directory /home/eedjsa/apl-1.9/src/workspaces
That directory exists.
)LIBS 2 ?
library reference 2 stands for directory /home/eedjsa/apl-1.9/src/wslib2
That directory is missing or not accessible.
See command )LIBS without arguments for details.*
*SVN 1878*.
Best Regards.
Jürgen
On 7/1/25 15:45, Hans-Peter Sorge wrote:
Hi Jürgen,
correct.
However as there is no simple command that returns the name of the
actually set LIB name
im parsing the return from ⍎')LIBS' for a proper Lib name.
It just makes handling LIB-changes programmatically inconvenient.
As ]LIB and ]LIBS return the same content, letting ]LIBS n return the
corresponding LIB-Path
could simplify (a little bit) the coding.
Anyhow as the parsing of )LIBS does the job I have a solution.
Best Regards
Hans-Peter
Am 01.07.25 um 12:53 schrieb Dr. Jürgen Sauermann:
Hi Hans-Peter,
*)LIBS* (i.e. without arguments) displays the directories for all
library reference numbers
*)LIBS root *(i.e. with one argument) sets the root directory for all
library
references. This root directory may then contain the sub directories
*workspaces*,
*wslib1*, *wslib2*, ... *wslib9* for the library numbers 0, 1, 2, ...
9 respectively,
*)LIBS N dir* (i.e. with two arguments *N* and *dir* (a directory)
sets the directory
for library reference number *N* to directory *dir*.
Therefore the old behavior of *)LIBS* was incorrect and was fixed at
some point in time.
Your example *)LIBS 0 ** sets library reference number *0* to
directory** *(which most likely
does not exist since the shell expands *** to all files).
Best Regards,
Jürgen
On 6/30/25 16:57, Hans-Peter Sorge wrote:
Hi
in the past *)LIBS 0 **
did return the set Library Path.
With SVN: 1876:1877M
I get
*)libs 0 ***
*LIBRARY REFERENCE 0 SET TO *
* )lib 0***
IMPROPER LIBRARY REFERENCE '0': No such file or directory
Currently there is no (documented?) simple way to retrieve the
lib-name.
Best Regards
Hans-Peter
