Stahlman Family wrote:
> Mingw (Msys) Bash 2.04.0(1)-release
> Microsoft Windows XP Home Edition Version 2002 Service Pack 2
>
>
> Perhaps I'm misunderstanding something, but the way I read the manual
> text on the case command, if anything is printed in the example below,
> it would be "2", since if the quotes around " foo bar " are not removed
> in the case pattern, then the first case is testing the string
> <space>foo<space>bar<space>
> against
> <double-quote><space>foo<space>bar<space><double-quote>
Not exactly. Strict quote removal is not performed. The behavior of
quoted characters is as in pattern matching: quoted characters match
themselves, even characters are have special meaning in pattern matching.
There is some internal process of turning, for instance, " foo bar "
into \ \f\o\o\ \b\a\r\ , but that is not the same as quote removal.
That becomes more clear when the pattern to be quoted is "*": quote
removal would turn that into * rather than \*, so you would not be able
to use "*" to match a literal * if quote removal were performed.
Posix is, as usual, more verbose about this than the bash manual page.
Chet
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
Live Strong. No day but today.
Chet Ramey, ITS, CWRU [EMAIL PROTECTED] http://cnswww.cns.cwru.edu/~chet/
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