I dont get it right, i always display only the first one, and i dont know how
to write a scalar variable.
I tried like this :
ssh [EMAIL PROTECTED] script2 -f "[EMAIL PROTECTED]"
It's not changing anything.
I m using bash.
Thank you.
Stephane Chazelas wrote:
>
> On Tue, Dec 09, 2008 at 09:14:51AM -0500, Chet Ramey wrote:
>> >
>> > Hello i would like to pass an array to my script command line argument,
>> but
>> > only the first element of the array is displayed. Here is my process :
>> >
>> > script1:
>> > my_array=(el1 el2 el3)
>> > script2 -f $my_array
>>
>> You're only passing the first element of the array to script2. An
>> unsubscripted word expansion expands to the first element of an array.
> [...]
>
> More exactly, an unsubscripted word expansion expands to the
> element of subscript 0 or to the empty string if that element is
> not defined.
>
> After
>
> a[12]=foo
>
> The first element is "foo", but $a expands to the empty string.
>
> $a is a shortcut for ${a[0]} and a=bar is a shortcut for a[0]=bar
>
> This is similar to ksh but different from zsh where arrays and
> scalars are of different types, and arrays are not scarse arrays
> but normal arrays. In zsh, a[12]=foo allocates an array of 12
> elements, the first 11 being empty; $a is the same as $a[*] and
> is the list of non-empty elements in $a. Doing a=foo, would
> change the type of $a to be a scalar, so you'd lose all the
> array elements. The OP's code is actually zsh (or rc/es) syntax,
> though it would make more sense to do:
>
> scalar -f "[EMAIL PROTECTED]"
>
> which would work the same in bash, ksh93 and zsh (and in zsh, it
> wouldn't discard the empty elements, contrary to $my_array).
>
> --
> Stéphane
>
>
>
>
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