Bill Gradwohl wrote:
> On Fri, 2009-04-24 at 13:50 -0400, Greg Wooledge wrote:
>> parameter=${paramter//[ $'\t']/}
>
> I experimented a bit. See the attachment.
>
>
> The first 3 dumpit outputs are expected. The next 2 are not. The last 2
> show what I would have expected from the previous 2.
I'm not quite sure what this is supposed to demonstrate. In the cases
where you have specified the tab character correctly ($'\t'), it's
converted into a tab before matching is attempted. You can tell this
because in the cases where you have not, either the literal `$' gets
removed, or the literal instances of \t in the value of parameter are
removed. Since there are no tab characters in $parameter, no tabs get
removed when you specify $'\t' correctly.
Chet
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
Chet Ramey, ITS, CWRU c...@case.edu http://cnswww.cns.cwru.edu/~chet/
