Peng Yu wrote: > I have the following script and output. The man page says "Return a > status of 0 or 1 depending on the evaluation of the conditional > expression expression." Therefore, I thought that the two printf > statements should print 1 and 0 respectively. But both of them print > 0. I'm wondering what [[ should return if it is not used with a if > statement.
The problem is that you have confused the character output to stdout with the exit code status return of the program. > $ cat main.sh > #!/usr/bin/env bash > > printf '%d\n' `[[ 10 -gt 1 ]]` > printf '%d\n' `[[ 1 -gt 10 ]]` The backticks invoke the command, save the character output to stdout, replace the backticks with that output. The exit code is not used in your example. The output of those is nothing. When printf evaluates nothing as an integer it resolves to 0 and therefore 0 is output. Look at this: $ [[ 10 -gt 1 ]] $ [[ 1 -gt 10 ]] Neither of those produce any output. $ printf '%d\n' "" 0 To print the exit code you would need something like this: $ [[ 10 -gt 1 ]] ; echo $? 0 $ [[ 1 -gt 10 ]] ; echo $? 1 Bob
