Hello.
Example:
---------------------------------------
#!/bin/bash
set -e -u -E -T
fun()
{
echo 'Execute really bad command:'
/bin/false
echo 'should not print this'
return 0
}
if ! fun; then
echo 'should catch fault here'
fi
fun
---------------------------------------
"should not print this" should not be printed (as I think) in any case.
But in first case, it's printed, in second - is not.
(I have tested in bash 2.0 ... 4.2.24)
Is any way to force "set -e" to work even in such cases?
If this question asked 1000 times, why not to answer in FAQ (
http://tiswww.case.edu/php/chet/bash/FAQ)?
--
Segmentation fault
