On 10/12/12 5:36 PM, Wladimir Sidorenko wrote:
> Ok, thanks. I'll notice this for the future. It's of course arguable,
> whether PIPESTATUS stores a true value, since the '!' inversion
> keyword gets ignored in this case. But if it was intended, than it's
> ok.
The case where PIPESTATUS stores only a single exit status is the
degenerate case. Pipelines have multiple elements.
What do you think should happen in the following case?
! exit 1 | exit 2 | exit 3
$? reflects only the status of the pipeline, which in this case is the
(inverted) status of the final command. Why should $PIPESTATUS not
reflect the actual exit statuses?
Chet
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU [email protected] http://cnswww.cns.cwru.edu/~chet/
