This might have the same fix. I guess Bash only checks for valid
variable names during expansion or initial assignment.
$ bash -xc 'typeset -n x; x=@ x=(ha ha); typeset -p @'
+ typeset -n x
+ x=@
+ x=(ha ha)
+ typeset -p @
declare -a @='([0]="ha" [1]="ha")'
Bash eventually catches it if you try using the variable so the harm is
minimal. I suppose you could wreck things for somebody evaluating the
output.
$ typeset -n x; x="_; y" x=foo; typeset -p "${!x}"; eval "$(typeset -p
"${!x}")"; echo "$y"
+ typeset -n x
+ x='_; y'
+ x=foo
+ typeset -p '_; y'
declare -- _; y="foo"
++ typeset -p '_; y'
+ eval 'declare -- _; y="foo"'
++ declare -- _
++ y=foo
+ echo foo
foo
--
Dan Douglas
