I think this is wrong: var= ; echo "${var/*/x}"
It should print x but it prints nothing.The attached patch fixes this, I hope it's ok. I don't know what's the correct behaviour in case $var is unset, but it's probably worth to look at, since bash prints nothing in that case too. --- xoxo iza
0001-replace-patterns-in-empty-strings.patch
Description: Binary data
