On Fri, Dec 18, 2015 at 7:05 PM, Krem <valk...@yahoo.com> wrote:
> Hi all,
>
> I have one folder and this folder contains several folders. Each sub
> folders
> contains 5 or 6 files. So i want count the number of rows within each
> file and produce an output.
>
> Assume the main folder called A and it has three subfolders folder1,
> folder2 and folder3.
> Folder1 has 4 files: file1, file2, file3 and file4.
>
> The same thing is for folder2 and folder3.
> Assume that file1 has 36 rows ( wc -l file1) =36.
> Assume that file2 has 50 rows ( wc -l file2) =50.
> Assume that file3 has 36 rows ( wc -l file3) =120.
> Assume that file4 has 50 rows ( wc -l file4) =15.
>
>
> I want the output
> mainfolder subfiolder filename # of rows
>
> A Folder1 file1 36
> A Folder1 file2 50
> A Folder1 file3 120
> A Folder1 file4 15
> A folder 2 filename1 ..
> ..
> ..
> ..
> A last_folder lasfilename ... .
>
> Can anyone help me out?
>
> Thanks in adv
> ance
>
>
Try this and see if it is close to what you want:
find . -type f | while read i;do echo -e "${PWD
##*/
} $(dirname ${i
}
| cut -b 3-
) $(basename ${i}) $(wc -l ${i})" ;done | cut -d " " -f 1,2,4,3
${PWD##*/} is the "mainfolder" ${PWD} is the entire name of the current
directory. ##*/ eliminates all character up to, and including the _last_ /
. This give you just the last node name. E.g /home/me/some/A ==> A
dirname ${i} | cut -b 3- gives the "subfolder" name. The "cut -b 3-" cuts
off the first two bytes, which is _normally_ always "./" given the syntax
of the find command. You may need to mess with this.
basename ${i} just gives the file name itself, with no directory aka
"filename"
wc -l -- you already know that.
the final cut command just rearranges the output into the order you wanted
it to be in.
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