On Mon, Feb 12, 2018 at 3:23 PM, Nikolai Kondrashov <spbn...@gmail.com>

>> Take a look at these links:
>>   - http://wiki.bash-hackers.org/commands/builtin/unset
>>   - http://www.fvue.nl/wiki/Bash:_Passing_variables_by_reference
> Thanks, Clark! However, I find it difficult to follow the explanation at
> the
> first link and even more difficult to connect it to this case. So I'm not
> sure
> I'm getting it right. Could you maybe explain what exactly happens in the
> code
> I posted?

Your code:

    inner() {
        unset res
        if [[ $1 == "set" ]]; then

    outer() {
        local res=
        inner "$1"
        echo "res: ${res[@]}"

The "unset" in inner() actually unsets the "res" in outer() and the
following assignment (to res[0] and res[1]) is actually assigning to the
global var "res". And in outer(), after calling inner(), its local "res" is
gone and it also referencing to the global var "res".

With 2 "unset" commands, even the global "res" is unset.

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