Date: Tue, 10 Jul 2018 18:46:32 -0400
From: Isaac Marcos <[email protected]>
Message-ID:
<ca+n9ptxfktmmqpabz+xmqk4pphix4x_yqy-w6tnyndr3ibo...@mail.gmail.com>
| set -- 34 034 0034 +34 +034 +0034 -34 -034 -0034 ;
| for i do printf '%6s' "$((10#$i))"; shift; done; echo
You really ought be only using POSIX defined sh operators,
from two more POSIX compatible shells (in this regard...):
jinx$ sh -c 'printf '%6s' "$((10#$i))"'
sh: arithmetic: unexpected '#' (0x23) in expression
jinx$ fbsh !*
fbsh -c 'printf '%6s' "$((10#$i))"'
fbsh: arithmetic expression: expecting EOF: "10#"
Leading "base#" is not part of the sh language at all, and so
should not be expected to work at all, let alone in any particular way.
kre
