On 7/15/19 6:19 PM, astian wrote:
>> I doubt it makes any difference to the timing, which I think
>> Chet has already answered, but it is worth pointing out that these
>> two commands ...
>>
>> printf '%s\n' "`printf %s "$i"`"
>> printf '%s\n' "$(printf %s "$i")"
>>
>> which (I believe)) are supposed to be the same thing, using the
>> different (ancient, and modern) forms of command substitution aren't
>> actually the same. In the first $i is unquoted, in the second it is
>> quoted. Here, since its value is just a number and IFS isn't being
>> fiddled, there is not likely to be any effect, but if you really
>> want to make those two the same, the first needs to be written as
>>
>> printf '%s\n' "`printf %s \"$i\"`"
>>
>> Such are the joys of `` command substitutions (just avoid them).
>>
>> kre
>
> Dear Robert Elz, I'm aware of several of its peculiarities and I typically do
> avoid them. However, is it true that $i is unquoted in the first case?
POSIX makes it undefined behavior, and different shells do it differently.
Bash makes the $i quoted within the `` string, as you discovered.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU c...@case.edu http://tiswww.cwru.edu/~chet/
