On 7/23/20 8:11 PM, Alexey Izbyshev wrote:
> Hello!
>
> I have a question about the following behavior:
>
> $ Z='a b'
> $ A=(X=$Z)
> $ declare -p A
> declare -a A=([0]="X=a b")
> $ A=(X$Z)
> $ declare -p A
> declare -a A=([0]="Xa" [1]="b")
>
> I find it surprising that no word splitting is performed in the first
> compound assignment. I realize that skipping word splitting may be
> desirable if a subscript is given (e.g. "A=([0]=$Z)") to make it consistent
> with normal variable assignment[1], but in this case it looks like a bug.
It's an assignment statement in a context where assignment statements are
accepted (which is what makes it different from `echo X=$Z', for instance),
but the lack of a subscript on the lhs makes it a special case. I'll take a
look at the semantics here.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU c...@case.edu http://tiswww.cwru.edu/~chet/
