> On Jan 8, 2021, at 3:50 AM, William Park <opengeome...@yahoo.ca> wrote:
>
> I don't know if it's a bug. Manpage says "local" builtin takes all the
> options that "declare" takes. But, "local -p var" doesn't print
> anything, where as "declare -p var" does.
>
> f1()
> {
> local a=123
> local -p a
> }
>
> f2()
> {
> local a=123
> declare -p a
> }
>
> f1 # prints nothing
> f2 # prints $a
Please specify your version of bash when posting to these lists.
According to the NEWS file, bash 5.1 behaves as you expect:
y. `local' now honors the `-p' option to display all local
variables at the current context.
https://git.savannah.gnu.org/cgit/bash.git/tree/NEWS#n79
vq
