On Fri, 2 Dec 2022 at 21:29, Ulrich Windl
<ulrich.wi...@rz.uni-regensburg.de> wrote:
> Surprisingly "declare XXX=$(false);echo $?" outputs "0" (not "1")
> There is no indication in the manual page that "declare" ignores
> the exit code of commands being executed to set values.
The above is not surprising at all.
'declare' is a builtin command. It succeeded.
$ help declare | tail -n 3
Exit Status:
Returns success unless an invalid option is supplied or a variable
assignment error occurs.
'man bash' explains this comprehensively.
The return value is 0 unless an invalid option is encountered, an
attempt is made to define a function using ``-f foo=bar'', an attempt
is made to assign a value to a readonly variable, an attempt is made to
as‐ sign a value to an array variable without using the compound as‐
signment syntax (see Arrays above), one of the names is not a valid
shell variable name, an attempt is made to turn off read‐ only status
for a readonly variable, an attempt is made to turn off array status
for an array variable, or an attempt is made to display a non-existent
function with -f.
Also, $(false) probably does not produce the value
of $XXX that you expect. Try running 'echo $(false)'.
