On Mon, Mar 27, 2023 at 04:43:09PM -0700, L A Walsh wrote:
> On 2023/03/27 13:28, Greg Wooledge wrote:
> > You're calling filter_ssh with no arguments, but trying to use "$@"
> > inside it to generate the ssh command.
> Isn't "$@" still valid? Originally I didn't have func-filterssh, it was
> inline.
Each function has its own private set of positional parameters ("$@" array)
independent of the main script's "$@". If you want the funtion to see
a copy of the script's arguments, you need to pass "$@" to it.
