On Wed, Nov 29, 2023 at 12:37:55AM +0000, Klaus Frank wrote: > One thing though, I probably should already know that, but why is a $0 > needed even though a command was already specified? Shouldn't the command > itself be $0?
It's simply how sh -c has always worked. The first argument after -c is the script to be executed. The second argument after -c becomes $0 of the script, the third becomes $1, and so on. If you want to pass positional parameters to the -c script, therefore, you must put *something* in the slot between the script and the parameters. That something becomes $0. Common choices are sh, bash, _ and x but you can use pretty much any string.
