I use often the value of LINEO in order
to know where to look for issues in a script.
Recently I discovered a bug.
Please consider the following 6 line script:
------------------------------------------------
#!/bin/bash
if ((1)); then
( : ) ; echo 1 $LINENO
fi
echo 2 $LINENO
------------------------------------------------
if executed it should print:
1 4
2 6
And indeed that's the output if I run it on openSUSE Leap 15.5
(bash 4.4). However if I execute it on openSUSE tumbleweed
(bash 5.2) the output is:
1 4
2 5
I compiled and tested several version of bash and the conclusion
is that the bug is not there up to bash 4.4.18 and it
shows up in bash-5.0-alpha and later releases.
In order to trigger the bug in your script you need:
1) a compound command executed in a subshell ( : )
2) included in if then fi
The LINENO variable will start to show an incorrect value immediatly after the
fi reserved word.
Example:
------------------------------------------------
#!/bin/bash
if ((1)); then
( : ) ; echo 1 $LINENO
:
#
echo 3 $LINENO
fi
echo 2 $LINENO
------------------------------------------------
correct output with 4.4:
1 4
3 7
2 9
wrong output with 5.x:
1 4
3 7
2 5
Please let me know if you need more infotrmation.
