On 6/16/25 12:51 PM, Lionel Cons wrote:
Why do these two lines differ in output? ${name} and ${name-} should
produce identical output if "name" exists as variable, or not?
They're not the same expansion, and the example you're using is not the same as your question.
$ (name='bar" x' ; name="${name-//\"/}" ; printf "%q\n" "$name")
'bar" x'
In this expansion, you get the unsplit value of `name', since it's set, and print it.
$ (name='bar" x' ; name="${name//\"/}" ; printf "%q\n" "$name")
'bar x'
In this expansion, you remove the double quote and print the result.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU c...@case.edu http://tiswww.cwru.edu/~chet/
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