On 31 Oct 2011, at 06:11, Vol Litwr wrote:
> //This code works with yacc but it doesn't work with bison -y. :-(
> //The problem is TAB---the compiler doesn't see it at the code of
> y.tab.c produced by bison
>
> %token DIGIT
> %left '+'
> %%
> list:
> | list '\n'
> | list expr '\n' {printf("%c%d\n", TAB, $2);}
> ;
> expr: DIGIT
> | expr '+' expr {$$ = $1 + $3;}
> ;
> %%
> #define TAB '\t'
>
> int yylex () {
> int c;
> while ((c = getchar()) == ' ' || c == TAB);
> if (isdigit(c)) {
> yylval = c - '0';
> return DIGIT;
> }
> return c;
> }
>
> int yyerror() {}
>
> main () {
> yyparse();
> }
This might be something for Paul Eggert to reply on: Bison only supports Yacc
as to what is in the POSIX standard I think.
The problem is here that the epilogue of the grammar file is copied by Bison
verbatim to the end of the parser implementation file. So apparently, the Yacc
you are using is doing it differently.
Hans
