On Wednesday 21 April 2004 05:02 pm, Jim Meyering wrote:
> dd is probably the best choice, then.
>
> Using two separate processes is best, unless you can
> find a reasonably large input block size that evenly divides both
> the initial offset and the number of bytes you want to output.
>
> Then dd will use lseek to skip past the initial 1*NUM bytes.
>
> ( dd ibs=1 skip=N_SKIP count=0 && dd ibs=4096 count=100725 ) < BIG > out
>
> since 4096 * 100725 == 412569600.

Very clever.  I'll give it a try.

Thanks,
Mordy
-- 
Mordy Ovits
Network Security
Bloomberg L.P.



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