On 11/07/2016 10:56 AM, Reuti wrote: >> You are correct that it states that, but it means that 'test' (with no >> expression at all) is what results in a false return (that is, an >> omitted expression is equivalent to zero arguments). 'test -s' is NOT a >> case of an omitted expression; your expression was '-s'. Since you >> provided exactly one argument, you are testing whether '-s' is the empty >> string (it is not, hence the true result). > > Doesn't -s refer to a FILE existence, it's not -z?
When there are TWO arguments, '-s "$file"' tests for whether file is empty, and '-z "$string"' tests for whether $string is empty. But here we are talking about ONE argument, '-s', which is non-empty. (Yes, the one-argument case is identical to using the two-argument -z "$string" case.) -- Eric Blake eblake redhat com +1-919-301-3266 Libvirt virtualization library http://libvirt.org
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