Peng Yu <pengyu...@gmail.com> writes:
> I find that "-exec test ..." can be slower than "-exec $(which test)
> ...". Is possible that `find` internally use "which", so that users
> don't need to explicitly call it?
It's possible, I suppose, but the semantics of -exec can be changed by
turning the program name into a specific path. Consider
find / -name rm -exec rm {} \;
As processing deletes files named 'rm', which program is executed by
"-exec rm" can change.
Also, there is no certainty that 'which' carries out exactly the same
search process as the kernel calls execlp()/execvp().
I can see that there are times when you'd want to do this, but it seems
to me that explicitly writing $(which prog) isn't difficult and makes
explicit how you're modifying the semantics of 'fimd'.
Dale
