Let's assume the following current folder: . | +---- a.txt | +---- b.txt | +---- c.txt
in which we issue the following command $ find . -depth -name a.txt -o -name b.txt We get the following result: ./a.txt ./b.txt -------- Problem 1 -------- By evaluating the expression according to the information in the manual of find the command should return also c.txt as part of the result. Let me explain my reasoning. The above command is equivalent to the following command: $ find . -depth -a -name a.txt -o -name b.txt and the expression is evaluated for each file, that is even for c.txt and because the result is known immediately after the evaluation of -depth (which always returns true) the command should print it to the standard output. Not having c.txt in the result it seems to me that find performs the following evaluation: $ find . -depth -a \( -name a.txt -o -name b.txt \) Is this correct? If so, then some information in the manual page should clarify that all global options are (probably) evaluated only once and before the rest of the expression. -------- Problem 2 -------- I've tried to use "-D tree" to see that is going on. The first section shows: Predicate List: [(] [-depth] [-a] [-name] [-o] [-name] [)] [-a] [-print] I deduce that before printing "Predicate list" section find elaborates the expression and adds a "-print". Correct. But, in this printed form the order of evaluation has the same problems as mentioned in the section "Problem 1" above. The same is true for the next sections "Normalized Eval Tree", "Optimized Eval Tree", etc. Thank you Cristian
