On Sun, Mar 28, 2010 at 10:50:38PM -0500, lyle lyle wrote: > Hi Guys, > > I write code in Fortran and found that I couldn't print an element's value > if the element wasn't in the first column. For example, > > There is an array A and its size is 5x3. In gdb, I can get its first column > elements' value with the command: p A(1, 1), until A(5, 1), because the > array is saved in memory according to columns. However, if I want to get > A(1, 2), then gdb showed the error message: no such vector element. > > I searched online and found that another person had reported this bug, > https://bugs.launchpad.net/ubuntu/+source/gdb/+bug/500691. > > I confirmed that both the version 6.8 and 7.1 had the same problem. > > I use gfortran 4.4.3, gdb 7.1, and Debian squeeze. > > Is there a patch for this bug? Can someone help me fix this problem? > > Thanks a lot, > Lyle
> program main > real a(5, 3) > do 12 i=0,4 > do 12 j=1,3 > a(i+1,j)=i*3+j > 12 continue > write(*,*)a(2,3) > end Somehow I feel I gave a workaround for this problem before: Each array regardless of its dimension can be unfolded to a one dimensional array by calculating the array element position. For your (n,m) dimensions you will get the one dimensional position k for coordinates (i,j) by k=n*j+i (counted from 0!). I haven't tried this and you should test the exact positons, but thats the way it should work. bye ingo _______________________________________________ bug-gdb mailing list bug-gdb@gnu.org http://lists.gnu.org/mailman/listinfo/bug-gdb
