why this indent result looks abnormal? when i drop the cast operator from source, it works well? why

[陈建锋]

line 38 in attachment

     1  Script started on 2007Äê08ÔÂ16ÈÕ ÐÇÆÚËÄ 09ʱ43·Ö40Ãë
     2  [EMAIL PROTECTED] /tmp>bash -version
     3  GNU bash, version 3.00.15(1)-release (i386-redhat-linux-gnu)
     4  Copyright (C) 2004 Free Software Foundation, Inc.
     5  [EMAIL PROTECTED] /tmp>uname -a
     6  Linux oracle.dev 2.6.9-22.ELsmp #1 SMP Mon Sep 19 18:32:14 EDT 2005 
i686 i686 i386 GNU/Linux
     7  [EMAIL PROTECTED] /tmp>indent -version
     8  GNU indent 2.2.9
     9  [EMAIL PROTECTED] /tmp>cat ~.//.indent.pro
    10  -ppi3
    11  -ip3
    12  -psl
    13  -sc
    14  -sob
    15  -pcs
    16  -bap
    17  -bad
    18  -bbb
    19  -ci2
    20  -ncdw
    21  -nce
    22  -i2
    23  -gnu
    24  -hnl
    25  -cs
    26  [EMAIL PROTECTED] /tmp>cat ./test_indent.sh 
    27  echo "void printGathShm (void *base) 
    28  { for (i = 0; i < MAX_ARRAY_SIZE; i++) { 
    29  p = (char *) base + i; }}" |
    30  indent -st
    31  [EMAIL PROTECTED] /tmp>sh ./test_indent.sh 
    32  void
    33  printGathShm (void *base)
    34  {
    35    for (i = 0; i < MAX_ARRAY_SIZE; i++)
    36      {
    37        p = (char *) base + i;
    38  }}
    39  [EMAIL PROTECTED] /tmp>exit
       
    40  Script done on 2007Äê08ÔÂ16ÈÕ ÐÇÆÚËÄ 09ʱ45·Ö07Ãë

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