V Mon, Apr 10, 2023 at 01:29:41PM -0600, Nicolas Bock napsal(a):
> The following code is aligned incorrectly using indent-2.2.12:
>
> ```C
> #include <stdlib.h>
>
> #define TYPED(name) name ## _typed
>
> typedef void matrix_t;
>
> void TYPED (testfunc) (void)
> {
> matrix_t*A = NULL;
> matrix_t*B = NULL;
> }
>
> void testfunc (void)
> {
> matrix_t*A = NULL;
> matrix_t*B = NULL;
> }
> ```
>
> ```console
> indent -par test.c
> ```
>
> ```diff
> --- test.c 2023-04-10 13:21:00.516535705 -0600
> +++ test-2.2.12.c 2023-04-10 13:21:04.172585827 -0600
> @@ -6,12 +6,13 @@
>
> void TYPED (testfunc) (void)
> {
> - matrix_t*A = NULL;
> - matrix_t*B = NULL;
> + matrix_t * A = NULL;
> + matrix_t *B = NULL;
> }
>
> -void testfunc (void)
> +void
> +testfunc (void)
> {
> - matrix_t*A = NULL;
> - matrix_t*B = NULL;
> + matrix_t *A = NULL;
> + matrix_t *B = NULL;
> }
> ```
>
> The pointer's indirection operator '*' for variable A is incorrectly
> aligned in the first function definition. This is a regression from
> indent-2.2.11.
>
I confirm it with 2.2.13. Because indent does not perform a macro expansion,
the reproducer can be reduced to:
/* If a function name is hidden with a parametrized macro, and a variable type
* is not a built-in type, then a first variable definition with a pointer of
* that type in the function block will have a star character misaligned.
* (indent -par) */
void TYPED (foo) (void)
{
bar *A = NULL;
bar *B = NULL;
bar *C = NULL;
}
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