Maestraccio <maestraccio <at> maestraccio.nl> writes:
> 2: Leave out all "7", "9" and/or "#11" when any higher number is present.
> So "C 7/b9/add13" will be "C b9 13" ({c:7 9- 13})
Ad 2: "7", "9" or "#11" without flats or sharps to be left out, of course.
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