Put this in a Makefile: foo.%bc: FIRST=first foo.a%c: SECOND=second foo.abc: THIRD=third
foo.abc: ; @echo $(FIRST) $(SECOND) $(THIRD) Run "make". We believe that it *should* print "first second third", but instead it prints "first third". If you swap the order of the first and second lines, it instead prints "second third". This is because Make only interprets one pattern-specific variable assignment for each target. This behavior does not seem to be documented, and we don't think it's correct. We've observed this behavior in make 3.77, 3.78.1, 3.79.1, and 3.80. We have a patch to fix the problem, if you're interested. -- Bob Byrnes e-mail: [EMAIL PROTECTED] Curl Corporation phone: 617-761-1200 1 Cambridge Center, 10th Floor fax: 617-761-1201 Cambridge, MA 02142-1612 _______________________________________________ Bug-make mailing list [EMAIL PROTECTED] http://mail.gnu.org/mailman/listinfo/bug-make
