Hi!
$ rpm -qf `which echo`
sh-utils-2.0-13
$ cat /etc/redhat-release
Red Hat Linux release 7.1 (Seawolf)
Is it correct behaviour for "echo" that
echo -en "\\\b"
prints out "\b" instead of a "\" which is erased by the subsequent
backspace immediately?
On the contrary, both
echo -en "\\"
and
echo -en "\b\\"
print out a backslash correctly.
---------- Forwarded message ----------
Date: Wed, 6 Jun 2001 23:24:58 +0200 (CEST)
From: Michael Schwendt <[EMAIL PROTECTED]>
To: "'[EMAIL PROTECTED]'" <[EMAIL PROTECTED]>
Subject: RE: Two bash programming questions
On 2001-06-06, Taylor, ForrestX wrote:
>> echo with "-e".
>
>
>That's what I have. From the original post:
>> [ $C == 0 ] && echo -e -n "\b\\"
>What I want is something like:
> [ $C == 0 ] && echo -e -n "\\\b"
>
>a \ followed by a backspace. This prints out \b.
Split it:
echo -en "\\" ; echo -en "\b"
Whether it's a bug, I don't know.
Notice, however, that a \b after a character erases that one
immediately. Doesn't look as nice as erasing the last char before
printing a new one.
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