On Thu, 3 Feb 2000, rain forest puppy wrote:
> SELECT B_Main,B_Last_Post FROM general; DROP TABLE general;
> SELECT * FROM general WHERE B_Number=$Number
... <snip> ...
>
> But in reality, it doesn't work. Not because the theory is wrong, but
> because the database user we're using doesn't have DROP privileges. And
Maybe I'm reading this wrong, but I've never been able to piggyback
commands through mysql/DBI execute()'s, regardless of newlines, and even
when I have privs:
This works:
my $dbh = DBI->connect("dbi:mysql:sec_test:localhost","foo","bar");
my @row = $dbh->selectrow_array("select foo_col from bar_table");
print STDERR "row = (@row)\n";
But this doesn't:
my @row = $dbh->selectrow_array("select foo_col from bar_table; select
foo_col from bar_table");
> the format of field='data', a numeric field doesn't use the '' (i.e.
> numeric_field='2' is invalid). The correct syntax for numeric fields in
> numeric_field=2. Ah ha! There's no quotes to deal with, and you can't
I can't verify this. I can quote numbers, and they work fine (Msql
modules 1.2.017, msyql 3.22.30, DBI 1.13). And pushing them through quote
yields the same results with strings (although I haven't looked at the
DBI/Msql source yet...):
(foo_col is an unsigned tinyint here)
$ cat ./mysql-test.pl
use DBI;
my $dbh = DBI->connect("dbi:mysql:sec_test:localhost","foo","bar");
my $number = int(2);
my $str = $dbh->quote($number);
print STDERR "string = ($str)\n";
my $num = $dbh->do("insert into bar_table (foo_col) values ($str)");
print STDERR "num inserted = ($num)\n";
$dbh->disconnect;
$ ./mysql-test.pl
string = ('2')
num inserted = (1)
(same goes for selects, updates, etc)
> Another area that needs to be verified is the table name. In our very
_definitely_
> sub scrubtable {
> ($data=shift)=~tr/a-zA-Z0-9.//cd;
> return $data;}
That's good, but you need to also make sure that your grant tables are set
up correctly and you only accept from a predefined list of tables, as I've
seen vulnerable statements like the following, that a simple scrub won't
take care of:
select t.*, p.foo, from $table t, another_table p where p.col = ?
The problem here is a combination of the * and that $table is based on
user-input, while an entire table may be viewed that shouldn't be.
> EXCEPTIONS! Passing user data straight into a SQL query is asking for
> someone to tamper with your database.
agreed.
-B
Barclay Osborn [EMAIL PROTECTED]
Lead Programmer / Site Security Officer
