Le 2001-02-07, Padmapani S Ganti écrivait : > I just wanted to add a thing to the prime number which i found > independently and i do not know whether this has been achieved earlier or > not but i have a way of proving that every prime is of the form > (int)sq.root(1+24n) Not very interesting, since every integer >= 12 is of that form... let x integer >= 12. (x+1)^2 = x^2 + 2x + 1 > x^2 + 24 Therefore there is one N = 1 + 24n which satisfies x^2 <= N < (x+1)^2 ie x <= sqrt (N) < x+1, which is the definition of x = int (sqrt (N)). Thomas. -- [EMAIL PROTECTED]
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